A

Step 1: Convert the distance between the Earth and the Moon into meters.
The distance is given as 3.85 × 10⁵ km.
We know that 1 km = 1000 m, so:
Distance = 3.85 × 10⁵ km × 1000 = 3.85 × 10⁸ m.

Step 2: Convert the time taken for one revolution into seconds.
The time period is given as 27.3 days.
We know that 1 day = 24 × 60 × 60 seconds = 86400 seconds.
Time period, T = 27.3 days × 86400 s/day = 2.35872 × 10⁶ s.

Step 3: Calculate the orbital velocity of the Moon.
The formula for the orbital velocity (v) of an object in circular motion is given by:
$$ v = \frac{2\pi r}{T} $$
where r is the radius (or distance), and T is the time period.
Substituting the values we have:
$$ v = \frac{2 \times 3.14 \times 3.85 \times 10^{8}}{2.35872 \times 10^{6}} $$
$$ v \approx \frac{2.41670 \times 10^{9}}{2.35872 \times 10^{6}} \approx 1024.60 \, m/s.$$

Step 4: Use the centripetal acceleration formula.
The centripetal acceleration (a) can be calculated using the formula:
$$ a = \frac{v^{2}}{r} $$
Substituting the values:
$$ a = \frac{(1024.60)^{2}}{3.85 \times 10^{8}} $$
$$ a \approx \frac{1049730.56}{3.85 \times 10^{8}} \approx 0.00273 \, m/s^{2}.$$

Step 5: Conclusion. The acceleration of the Moon with respect to the Earth is approximately 0.00273 m/s².